Math, asked by manchemindira, 2 months ago

The acceleration due to gravity on the surface of moon is 1.7 m s−2. What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s? (g on the surface of earth is 9.8 m s−2)


I need in log and antilog solveing pl​

Answers

Answered by yogendrasingh6400
0

Answer:

iAa conlliou tumlion.Amy ondJion alkays vudutin ithku TRUE OR uniiom luinA the {rst valuL ifthe Cendition TRUE amd AheÅcend aus eE walusta Aa FALSE. LSE.i Apecli enaluati) te Eaample:'aIF (AL250, Ls0, ieo) his mlan hat he value im cull AL ruatou than So,tnm Valu so stlom

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