Question

The acceleration due to gravity on the surface of the planet is 5 ms1 and the radius of the planet is 5000 km. What will be the

escape velocity from the surface of this planet? ​

Answer 1

Answer:

Given that,

Mass of the earth =M

Radius of the earth = R

We know that,

g=

R

2

GM

Now, mass and radius is double

g

′

=

4R

2

G2M

g

′

=

2R

2

GM

g

′

=

2

1

g

Hence, the acceleration due to gravity on the surface of a planet is

2

1

g