The acceleration for a spherical object while falling in a
viscous medium can be:
a) a=g
b) a=0
c) a<g
d) All of these
Answers
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0
Answer:
In case of spherical ball
m=
3
4
πr
3
ρ
keeping m constant, if r is halved, ρ will increased by a factor of 8;
If buoyancy is neglected,
V
T
∝r
2
ρ; otherwise V
T
∝r
2
(ρ−ρ
o
)
⇒
V
T
V
T
′
=
r
2
ρ
r
′
2
ρ
′
⇒
V
T
V
T
′
=
r
2
ρ
(
2
r
)
2
8ρ
⇒
V
T
V
T
′
=
r
2
ρ
2r
2
ρ
⇒
V
T
V
T
′
=2
⇒V
T
′
=2V
T
⇒
V
T
′
=2v
Explanation:
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