Question

The acceleration of a body is given by a=3t^2+2t+5.Calculate its velocity at time t=2s.​

Answer 1

Answer:

Explanation:

:)

Answer 2

Answer:

Velocity at 2 sec will be 22 m/s

Explanation:

In context to the question ;

we have to calculate the velocity at time = 2 sec

given;

a=3t²+2t+5

we know that ;

acceleration is equal to rate pf change of velocity wrt time

a = dV / dt

by putting this in place of a , we get;

$\int\limits^a_b {dV / dt}$  =   $\int\limits^a_b {3t²+2t+5}$

$\int\limits^0_v {dV}$  =   $\int\limits^0_2{(3t²+2t+5)} \,dt$

[V - 0 ] = 3 [ t³/3 ]₀²  +2 [ t²/2 ]₀² + 5 [t]₀²

V = [t³]₀²  + [ t² ]₀² + 5 [t]₀²

V = [2³-0³] +[2²-0²] + 5[2-0]

V = 8+ 4 + 10

V = 22 m/s

Therefore, velocity at 2 sec will be 22 m/s