Question

The acceleration of a body whose speed increases from 36 km/h to 72 km/h in 2 seconds is :

Answer 1

Answer:-

• Initial velocity=u=36km/h
• Final velocity=v=72km/h

Convert to m/s

$\\ \sf\longmapsto 36\times \dfrac{5}{18}=10m/s$

$\\ \sf\longmapsto 72\times\dfrac{5}{18}=20m/s$

• Time=t=2s

We know that

$\boxed{\sf Acceleration=\dfrac{v-u}{t}}$

$\\ \sf\longmapsto Acceleration=\dfrac{20-10}{2}$

$\\ \sf\longmapsto Acceleration=\dfrac{10}{2}$

$\\ \sf\longmapsto Acceleration=5m/s^2$

Answer 2

Answer:

initial speed=36km/h

final speed=72km/h

time taken=2second

acceleration=?

a=v-u/t

a=72-36/2=36/2=18km/h

a=18km/h