Question

The acceleration of a car that comes to stop from a velocity of 10 m/s in distance of 25 m is ?

Answer 1

Answer:

v=0

a=?

s=25m

u=10m/s

V=U+at

0= 10+a×25

-10/25=a

-2/5=a

Answer 2

V^2 - u^2 = 2as

0 - 100 = 2(a)(25)

a = -2

Obviously the car is retarding hence -ve acc.