Question

The acceleration of a particle in m/s² is given by a = 3t²+2t+2, where t is in sec. If the particle starts with a velocity v = 2 m/s at t = 0, then find the velocity at the end of 2 sec.​

Answer 1

Answer:

dv/dt =a

v = t^3 + t^2+ 2t

at t = 2s

v = 16 m/s

V= u + v

V = 18m/s

Hope you got it

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