Question

The acceleration of a particle in ms 2 is given by a=3t2+2t+2

Answer 1

Answer:

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Answer 2

a=dv/dt

a=3t^2+2t+2

dv=a*dt

dv=(3t^2+2t+2)dt

integrating both sides we get

V=3xt^3/3+2t^2/2+2t=t^3+t^2+2t+C(constant)

at t=o

v=2m/s

2=0+c

c=2

V=t^3+t^2+2t+2

at t=2

V=8+4+4+2

=18