Question

The acceleration of a particle in SHM is 0.8ms-2, when its displacement is 0.2m.
The frequency of its oscillation is
1)
$\sqrt{2 \div \pi}$
2)
$2 \div \pi$
3)
$1 \div \pi$
4)
$1 \div 2\pi$

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Answer 1

Explanation:

3)

$1 \div \pi$

Answer 2

Answer:

Option 3) is the right answer

Explanation:

For SHM,

a=ω²y

where,

      a is acceleration

      ω is angular frequency

       y is displacement

we know,

         ω=2πυ

from the eq.

        0.8 =4π²υ² * 0.2

          υ=1/π

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