Physics, asked by aevalerianoo, 7 months ago

The acceleration of a particle is defined by the relation a = -k/x. It has been experimentally determined that v = 15 ft/s when x = 0.6 ft and that v = 9 ft/s when x = 1.2 ft. Determine (a) the velocity of the particle when x = 1.5 ft, (b) the position of the particle at which its velocity is zero.

Answers

Answered by aanchaksharma2345
0

the explanation of a practice is Defined by the relation is equals to minus ke upon it has been extremely tree determined that we equals to 15 active upon as when X is equals to 0.6 ft and their V is equal to 9 ft upon as when X is equals to 1.2 ft determined a the velocity of the practice eyes when X is equals to 1.5 ft be the position of the practices at which is awake Unity in

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