The acceleration of a particle is increasing linearly
with time t as bt. The particle starts from origin
with an initial velocity v.. The distance travelled by
the particle in time t will be
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Answer:
here it is given that a=bt
wkt, a=
change in time
change in velocity
=
dt
dv
∴
dt
dv
=bt now integrating this we will get v
v=
2
bt
2
+c
At t=0 s, v=v
0
, Thus v
0
=c
∴v=
2
bt
2
+v
0
Now. v=
change in time
change in position
=
dt
ds
=
2
bt
2
+v
0
∴ds=(
2
bt
2
+v
0
)dt
∴ Integrating the above we get, s=
6
bt
3
+v
0
t+c
′
at t=0, s=0∴c
′
=0
i.e. s=
6
bt
3
+v
0
t
Explanation:
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