Question

The acceleration of a particle is increasing linearly
with time t as bt. The particle starts from origin
with an initial velocity v.. The distance travelled by
the particle in time t will be
​

Answer 1

Answer:

here it is given that a=bt

wkt, a=

change in time

change in velocity

=

dt

dv

∴

dt

dv

=bt now integrating this we will get v

v=

2

bt

2

+c

At t=0 s, v=v

0

, Thus v

0

=c

∴v=

2

bt

2

+v

0

Now. v=

change in time

change in position

=

dt

ds

=

2

bt

2

+v

0

∴ds=(

2

bt

2

+v

0

)dt

∴ Integrating the above we get, s=

6

bt

3

+v

0

t+c

′

at t=0, s=0∴c

′

=0

i.e. s=

6

bt

3

+v

0

t

Explanation:

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