The acceleration of a particle is increasing linearly with time t as bt. the particle start from origin with an initial velocity v0 the distance travelled by the particle in time t will be
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Answered by
7
v = u + at
v = at [ u = 0 ]
at = bt
a = b
s = ut + 1/2at²
s = 1/2bt² [ u = 0 ]
Answered by
3
Answer:
dvdt=bt⇒dv=bt dt⇒v=bt22+K1 At t=0, v=v0⇒K1=v0 We get v=12bt2+v0
t=0, x=0⇒K2=0 ∴x=16bt3+v0t
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