The acceleration of a particle moving in a straight line varies with displacement as a=2s, velocity of the particles is zero displacement. Find the corresponding velocity displacement equation.
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Answer:
Correct option is
B
υ=±
2
s
If s be the displacement , v be the velocity and a be the acceleration then we will have following relation, a=v
ds
dv
putting a=2s and integrating we get ∫
s=0
s
2sds=∫
v=0
v
vdv
note-
It was given that velocity(v) was zero at zero displacement (s)
so we used v=0 at s=0 in the integration equation above.
after integration we get s
2
=
2
v
2
or v=±
2
s
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