The acceleration of a particle moving in a straight line is a=4-2v, where v is the speed of particle at any time t. The max. Velocity is?
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Answered by
75
For maximum velocity
dv/dt = 0
a = 4 - 2v
dv/dt = 4 - 2v
0 = 4 - 2v
v = 2
Maximum velocity is 2 m/s (If everything was measured in SI units)
dv/dt = 0
a = 4 - 2v
dv/dt = 4 - 2v
0 = 4 - 2v
v = 2
Maximum velocity is 2 m/s (If everything was measured in SI units)
Answered by
6
Answer:
Differentiate the given expression to find tge aximum velocity
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