Question

The acceleration of a particle moving only on a horizontal xy plane is given by   3 4 ˆ ˆ a ti tj , where a is in meters per

second-squared and t is in seconds. At t  0 , the position vector ˆ ˆ   (20.0m) (40.0m) 

r i j locates the particle, which

then has the velocity vectors v 



ˆ ˆ v i j (5.00 m / s) (2.00 m / s)  . At t  4.00s , what are (a) its position vector in unit-

vector notation and (b) the angle between its direction of travel and the positive direction of the x-axis?​

Answer 1

Answer:

I remember you do ur work yourself

from your teacher do it by yourself otherwise ask from me