The acceleration of a particle,starting from rest,varies with time according to the relation a=kt+c.Then the velocity v of the particle after a time t will be...
Plz solve to be the brainliest
Answers
Answered by
1
integrating from 0 to t we get v = (kt^2)/2 + ct
I think this is the answer ....
I think this is the answer ....
Anonymous:
This should be it, cuz you have not given any numerical value.
Answered by
2
a = dv/dt or v = ∫a*dt = ∫(kt+c)*dt
v = kt²/2 + ct
v = kt²/2 + ct
yes
1/2*kt^2+ct
Similar questions