Physics, asked by Rojalin3850, 6 months ago

The acceleration of a particle which is moving along a straight line is given by a = -kv0.4, where a is in meters per second squared, k is a constant, and v is the velocity in meters per second. Determine the velocity as a function of both time t and position s. Evaluate your expressions for t = 2.6 sec and at s = 3 m, if k = 0.9 m0.6 sec-1.6 and the initial conditions at time t = 0 are s0 = 2 m and v0 = 3.9 m/sec. v(t=2.6s) = v(s=3m) =

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Answered by abcd5490
2

Answer:

a77

Explanation:

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