Physics, asked by sagarkppatil, 10 months ago

The acceleration of a point on the rim of flywheel 1 m in diameter, if it makes 1200 revolutions per second is??

PLEASE ANSWER IN DETAIL

Answers

Answered by OfficialPk
1

Explanation:

given

w = 1200 rev/min

=1200×2pi/60

=40 pi rad/sec

given radius = 0.5m

centripetal accelration =rw^2

=0.5 × 1600pi^2

=800pi^2

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