Question

The acceleration of a train moving with constant speed of 40m/s on a path of radius 160 m

Answer 1

There are 2 components of acceleration.
Towards center: V2/R = 40 x 40 /400 = 4 m/s2
Tangent( orthogonal to center) = 3 m/s2
Resultant of 1 and 2 above = 5 m/s2