Physics, asked by zainabzahra235, 11 months ago

the acceleration of an electron moving with uniform speed of one thousand meter per second at right angles to magnetic field of flux density nine tesla, is given by ?​

Answers

Answered by shagundinani
2

Explanation:

What is the mechanism by which one magnet exerts a force on another? The answer is related to the fact that all magnetism is caused by current, the flow of charge. Magnetic fields exert forces on moving charges, and so they exert forces on other magnets, all of which have moving charges.

Right Hand Rule 1

The magnetic force on a moving charge is one of the most fundamental known. Magnetic force is as important as the electrostatic or Coulomb force. Yet the magnetic force is more complex, in both the number of factors that affects it and in its direction, than the relatively simple Coulomb force. The magnitude of the magnetic force F on a charge q moving at a speed v in a magnetic field of strength B is given by

F = qvB sin θ,

where θ is the angle between the directions of v and B. This force is often called the Lorentz force. In fact, this is how we define the magnetic field strength B—in terms of the force on a charged particle moving in a magnetic field. The SI unit for magnetic field strength B is called the tesla (T) after the eccentric but brilliant inventor Nikola Tesla (1856–1943). To determine how the tesla relates to other SI units, we solve F = qvB sin θ for B.

B

=

F

q

v

sin

θ

Because sin θ is unitless, the tesla is

1

T

=

1

N

C

m/s

=

1

N

A

m

(note that C/s = A). Another smaller unit, called the gauss (G), where 1 G = 10−4 T, is sometimes used. The strongest permanent magnets have fields near 2 T; superconducting electromagnets may attain 10 T or more. The Earth’s magnetic field on its surface is only about 5 × 10−5 T, or 0.5 G.

The direction of the magnetic force F is perpendicular to the plane formed by v and B, as determined by the right hand rule 1 (or RHR-1), which is illustrated in Figure 1. RHR-1 states that, to determine the direction of the magnetic force on a positive moving charge, you point the thumb of the right hand in the direction of v, the fingers in the direction of B, and a perpendicular to the palm points in the direction of F. One way to remember this is that there is one velocity, and so the thumb represents it. There are many field lines, and so the fingers represent them. The force is in the direction you would push with your palm. The force on a negative charge is in exactly the opposite direction to that on a positive charge.

The right hand rule 1. An outstretched right hand rests palm up on a piece of paper on which a vector arrow v points to the right and a vector arrow B points toward the top of the paper. The thumb points to the right, in the direction of the v vector arrow. The fingers point in the direction of the B vector. B and v are in the same plane. The F vector points straight up, perpendicular to the plane of the paper, which is the plane made by B and v. The angle between B and v is theta. The magnitude of the magnetic force F equals q v B sine theta.

I hope it will help uh...

Answered by CarliReifsteck
0

The acceleration of electron is 1.58\times10^{15}\ m/s^2

Explanation:

Given that,

Speed = 1000 m/s

Magnetic flux = 9 T

We need to calculate the magnetic force

Using formula of magnetic force

F=qvB\sin\theta

Where, v = speed

B = magnetic field

Put the value into the formula

F=1.6\times10^{-19}\times1000\times9\times\sin90

F=1.44\times10^{-15}\ N

We need to calculate the acceleration of electron

Using formula of force

F =ma

a=\dfrac{F}{m}

Put the value into the formula

a=\dfrac{1.44\times10^{-15}}{9.1\times10^{-31}}

a=1.58\times10^{15}\ m/s^2

Hence, The acceleration of electron is 1.58\times10^{15}\ m/s^2

Learn more :

Topic : magnetic force

https://brainly.in/question/12191845

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