Question

the acceleration of an electron of mass m and charge e moving with uniform speed v at right angle to a magnetic flux of flux density is given by?​

Answer 1

Given info : the acceleration of an electron of mass m and charge e moving with uniform speed v at right angle to a magnetic field.

To find : The magnetic flux density is ...

solution : electron is moving with uniform speed v at right angle to a magnetic field, due to this, electron moves in a circular motion because a magnetic force always acts radially inward.

at equilibrium,

magnetic force = centripetal force

⇒Bqv = mv²/r

where B is magnetic field intensity, q is charge , v is speed of charge , m is mass of charge and r is radius of circular path

here, q = e,

so, Ber = mv

⇒B = mv/er

we know, flux density is also known as magnetic field intensity.

so, flux density would be mv/er , where r is the radius of circular path.

Answer 2

Answer:

B= qvb

Explanation: