the acceleration of aparticle is increasin linerly with time as t= bt the particle start from origin with ainitial velocity v the distance travelled by the particle at any instant t
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Answered by
1
d2s/dt2 =bt
intigrate
V= ds/dt = bt2/2 +c
at t=0 V=U
so U =0 +c
ds/dt = bt2/2 +U
furthet intigrate
s= b/6 t3 +Ut +d
at t=0 s=0
so d=0
S =b/6 t3 +Ut
intigrate
V= ds/dt = bt2/2 +c
at t=0 V=U
so U =0 +c
ds/dt = bt2/2 +U
furthet intigrate
s= b/6 t3 +Ut +d
at t=0 s=0
so d=0
S =b/6 t3 +Ut
Answered by
0
S=bvt+1/2ab^2t^2 from formula s=ut+1/2at^2 where u=v from question
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