Question

the acceleration of block B in the figure will be
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Answer 1

Answer:

Explanation:

Let T be the tension acting throughout the string. And also a and b be the accelerations of block A and B respectively. So considering the forces on A we can write F-2T= 2ma.............(1) Again considering the forces on B we get 3T = 4mb.............(2) Due to application of force for small interval of time t , the displacement of A will be =1/2at^2 and the displacement of B will be =1/2bt^2. During this time work done by 2T and 3T will be same Hence 2T×1/2at^2=3T×1/2bt^2 => 2a= 3b..........(3) From (1) and (2) we get   F - (8/3)mb= 2ma......(4) Combining (3) and (4) we get F -(8/3)mb = 3mb =>(17/3)mb =F ÷> b = (3F)/(17m) Inserting F =17N and m =1kg we get Acceleration of B , b= 3m/s^2 Read more on Sarthaks.com - https://www.sarthaks.com/192675/the-acceleration-block-the-above-figure-assuming-surfaces-and-the-pulley-and-are-all-smooth