The acceleration of bus between point A & B may be :-
(a) 10 m/s2 (b) 20 m/s2 (c) 40 m/s2 (d) 0 m/s2
please help
Answers
Answered by
1
Explanation:
Answer
Let man will catch the bus after time t.Since the distance from man position is same for both at time t
⇒ Distance covered by bus = Distance covered by man -48
⇒
2
1
at
2
=vt−48
⇒
2
1
(1)t
2
=10t−48
⇒t
2
−20t+96=0
⇒(t−12)(t−8)=0
⇒t=8s (minimum value) or t=12s
So,at t=8s,the man will catch the bus
Answered by
1
Answer:
dude please give more details like what is the path of the bus..if it is a circular path then the acceleration will be 0m/s but if there is some time given then use the formula from sci t.b
formula=final velocity-starting velocity divided by time taken
Explanation:
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