Question

The acceleration of Cheetah if it acquires the velocity of 135 kmph with in 2s after the start

Answer 1

Answer:

here u= o and v= 135 kmph

so, a= (v-u)/t

= (135-0)/2

=67.5 km/ h^-2

Answer 2

Since the cheetah started from rest

Therefore , it's initial velocity(u)=0

Final velocity(v)=135 kmph=135*5/18=75/2 mph

Time taken (t)= 2s

acceleration=v-u/t =75/2-0/2=18.75 m/s²