Question

the acceleration of particle having mass 18kg is given as functions of time as a(t)=t/(9+t2) m/s for t>0 maximum net force which act on particle

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Answer 1

Explanation:

a=5m/s

2

alongnorth,thus,velocityalongeastwon

′

tchange

t=2s

u=10m/salongeast

displacementalongnorth=

2

1

at

2

=10m

displacementalongeast=ut=20m

totaldisplacement=

10

2

+20

2

=10

5

m

velocityalongnorth=at=10m/s

finalvelocity=10

i

^

+10

j

^