Question

the acceleration of particle in rectilinear motion is defined by t=3t^2-4t^3 given that at t=0 , v=0 and at t=1 sec , s=0 write equation of motion

Answer 1

v=3t³+t-(1/t²)

Therefore the differentiation

Accleration =d(v) /dt=d(3t³+t-(t-2))/dt

=9t²+1+2t-3

At t=2secs, acceleration of the particle=9(2)2+1+2(2)-3=36+1+2(1/2×2×2)=37+1/4=37.25m/s²

We know that F=MA

Hence net force acting on the body =(5kg)(37.25m/s²)=186.25 newtons

Hence Answer 186.25 Newton

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