Question

The acceleration of particle varies with time as:
a(t) = 3+ + 4
If the initial velocity of particle is 2m/s, find the velocity of particle at t= 3 sec.
0 41 m/s
O 4 m/s
0 39 m/s
© 27 m/s​

Answer 1

Answer:

41 m/s

Explanation:

velocity = ∫a .dt

       = ∫(3t² + 4) dt

       = t³ + 4t + C

         

At t = 0(initially), velocity is 2 m/s

        2  = 0³ + 4(0) + C

         2 = C

Therefore, at t = 3

velocity = 3³ + 4(3) + C

   = 27 + 12 + 2     {C=2}

   = 41 m/s