The acceleration of the body is zero, what is the nature of its distance time graph.
Plz show the graph.
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You dont have to memorize that its a linear. Try imagine plotting the graph of it (thats how you understand WHY is it linear)
As we know -- acceleration is the rate of change of VELOCITY. and based on your question, a=0
Say time as x axis, velocity as y axis. Does velocity change if a=0? NO. If v=5m/s, when t=0 its 5m/s; t=99 its still 5m/s. So imagine plotting this graph, you'll get? A horizontal straight line, with y-intercept as the velocity (5m/s)
Velocity is the rate of change of DISPLACEMENT
Say again time as x axis but DISPLACEMENT as y axis. Is velocity present? YES, if v=0, when t=0, s=0. If v=5m/s, when t=0, s=5m; t=1, s=10m; t=2, s=15m....................... Plot this in the graph, you'll get? a directly proportional graph (if t=0 is the moment of movement is started, linear if not)
***find the gradient of the 2 graphs. y axis / x axis what would you get? ;)
As we know -- acceleration is the rate of change of VELOCITY. and based on your question, a=0
Say time as x axis, velocity as y axis. Does velocity change if a=0? NO. If v=5m/s, when t=0 its 5m/s; t=99 its still 5m/s. So imagine plotting this graph, you'll get? A horizontal straight line, with y-intercept as the velocity (5m/s)
Velocity is the rate of change of DISPLACEMENT
Say again time as x axis but DISPLACEMENT as y axis. Is velocity present? YES, if v=0, when t=0, s=0. If v=5m/s, when t=0, s=5m; t=1, s=10m; t=2, s=15m....................... Plot this in the graph, you'll get? a directly proportional graph (if t=0 is the moment of movement is started, linear if not)
***find the gradient of the 2 graphs. y axis / x axis what would you get? ;)
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