the acceleration produced, if the friction is negligible. force. The mass of each box 10 x 10 kg. Calculate the value of An object of 2 kg is placed at rest. How much force must be applied on it so that a velocity of 4 m/s may be produced in it in 4 s?
Answers
Answer:
Horizontal force,F=600 N
Mass of body A, m
1
=10 kg
Mass of body B, m2=20 kg
Total mass of the system, m=m1+m2=30 kg
Using Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:
F=ma
a=
m
F
=
30
600
=20m/s
2
When force F is applied on body A:
The equation of motion can be written as: F−T=m
1
a
T=F−(m
1
)a
=600−10×20=400 N (i)
When force F is applied on body B:
The equation of motion can be written as:
F−T=m
2
a
T=F−(m
2
)a
T=600−20×20=200 N (ii)
which is different from value of T in case (i). Hence our answer depends on which mass end, the force is applied.
Answer:
2N of force should be applied. Please mark me as brainliest.
Explanation:
F = ma (Newton's 2nd Law)
[or F = momentum/time ( if it is given in your tb), but momentum is
mass x velocity, so it is
m x v/t. But v/t is a, so you will get F = ma]
m = 2kg
a = change in velocity/time = +4m/s/4s
= 1m/s^2
F = 2kg x 1m/s^2 = 2kgm/s^2 = 2N