Question

The acceleration time graph of a particle moving in a straight line is shown in figure. Of the initial velocity of particle is 20m/s in positive x- direction, then find the speed of the particle at t=30s( in m/s)

​

Answer 1

$\large \rm {\underbrace{\underline{Elucidation:-}}}$

$\sf \blue {\underline{\underline{Provided\: that:-}}}$

➻Initial velocity of the particle(u)=20m/s

➻Time interval(t)=30 seconds

➻According to the graph given above,

➻Acceleration of the particle (a)=$\sf {5m/s^{2}}$

$\sf \pink {\underline{\underline{To\: determine:-}}}$

➻The speed of the particle,i.e,

➻Final velocity of the particle(v)=?

$\sf \purple {\underline{\underline{Using\: 1^{st}\: Kinematic\: equation:-}}}$

$\to \sf {\fbox{\underline{v=u+at}}}$

➻Supplanting the given values,

$\to \sf {v=20+5×30}$

$\to \sf {v=20+150}$

$\implies \sf \green {\fbox{\underline{v=170}}}$

$\sf \orange {\underline{\underline{Henceforth,}}}$

➻The speed of the particle i.e, the final velocity of the particle comes out to be 170m/s respectively.