The acceleration to the block is 2 m/s when the force is applied. The coefficient of kinetic friction between the block and plane is u = 0.25. Calculate the magnitude of force P if the mass of the block is 100 kg
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Answer:
Let us first calculate the limitation and kinetic friction between various surfaces. Between 3 kg and ground:
f
l
1
=f
k
1
=μ
1
(2+3)g=0.1×5g=5N
Between 2 kg and 3 kg:
f
l
2
=f
k
2
=μ
2
g=0.2×2g=4N
Let us first assume that both blocks move together with common accleration a.
a=
2+3
5+10−f
k
1
⇒a=
5
15−5
=2ms
2
Now let us see how much friction force is required between 2kg and 3kg for common acceleration a.
5−f
2
=2a⇒5−f
2
=2×2⇒f
2
=1N
Since f
2
<f
l2
,
1. Both blocks will move together with common accelerationa=2ms
−2
2. Friction between 2kg and 3 kg =f
2
= 1N Friction between 3 kg and ground = f
k
1
= 5N
Explanation:
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