the acceperation of a particle is increasing linearly with time t as bt. the particle starts from origin with an initial velocity vo. the distance travelled by the particle in time t will be
Answers
Answered by
0
Answer:
here it is given that a=bt
wkt, a=
change in time
change in velocity
=
dt
dv
∴
dt
dv
=bt now integrating this we will get v
v=
2
bt
2
+c
At t=0 s, v=v
0
, Thus v
0
=c
∴v=
2
bt
2
+v
0
Now. v=
change in time
change in position
=
dt
ds
=
2
bt
2
+v
0
∴ds=(
2
bt
2
+v
0
)dt
∴ Integrating the above we get, s=
6
bt
3
+v
0
t+c
′
at t=0, s=0∴c
′
=0
i.e. s=
6
bt
3
+v
0
t
Similar questions