Question

the accl time graph of a particle moving with initial velocity 20m/s is shown below the velocity of body at t=20s​

Answer 1

Answer:

average velocity is 25m/s so distance will be 25×20=500m

now finding area of the graph between velocity and time graph we get

area of two triangles + area of rectangle.

2.

2

1

t.5.t+(25−2t).5t=500=>t

2

−25t+100

=>t=5

so option B is answer.