Question

the accleration of a particle is defined by relation a=8v, at t=0 verocity is 1m/s

Answer 1

Answer:

$a = \frac{dv}{dt} = 8v \: \: (given) \\ \\ \frac{dv}{v} = 8dt \\ \\ \int _{v = 1} ^{v = v} \frac{dv}{v} = 8 \int _{t = 0} ^{t=t} dt \\ \\ ln(v) = 8t \\ \\ \huge{v = {e}^{8t} }$