Question

The accommodation power of the eye lens of a young man whose far points is infinity can vary from 40d to 44d.What is distance of retina of the of young man

Answer 1

Answer:

2.5 cm Gradually

Explanation:

When the eye is fully relaxed, focal length of eye lens,

f₁ 1 1 = = P₁ 40 m = 0.025 m = 2.5 cm.

Hence distance of retina from eye lens = 2.5 cm.

*Hope it will help you*

Thanks!