Chemistry, asked by HarshitMall6893, 11 months ago

the acid ionisation constanrt fr zncl2 is k = 10^-9calculate the ph of 0.0001 molar solution of zncl2

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the acid ionisation constanrt fr zncl2 is k = 10^-9calculate the ph of 0.0001 molar solution of zncl2 has to be sulphide ores.

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