Question

The activation energy for a reaction at the temperature T K was found to be 2.303 RT J mol–1. The ratio of the rate constant to Arrhenius factor is ______. [Karnataka CET ​

Answer 1

Answer:

0.1 will be the ratio.

Explanation:

We know that the Arrhenius equations is K =Ae^-Ea/RT. Which on taking ln on both the sides will be lnK = lnA - Ea/RT.

On solving we will get that lnK - lnA = Ea/Rt or lnK/A = -Ea/RT which we know that the Ea is 2.303RT so lnK/A= - 2.303RT/RT hence lnK/A = -1 so, now on making it into log we will have  K/A = -1 or 0.1 will be the value of ratio of rate constant to Arrhenius factor.