Question

The activation energy for a reaction at the temperature TK was found to be 2.303 RT J Mol-1. The ratio of the rate constant to Arrhenius factor is

Answer 1

Heya,

We know,

Rate constant (k) is related to Arrhenius factor (A) by

$k = a {e}^{ \frac{ - ea}{rt} }$

where ea = activation energy

$k = a {e}^{ \frac{2.303rt}{rt} }$

Hence,

$\frac{k}{a} = {e}^{ - 2.303}$ = 1/10

Regards

Kshitij