Question

The activation energy for the reaction
2 HI(g) → H2+I2 (g)
is 209.5 kJ mol-1 at 581K.Calculate the fraction of molecules of reactants
having energy equal to or greater than activation energy?​

Answer 1

Answer:

In the given case:

Ea = 209.5 kJ mol - 1 = 209500 J mol - 1

T = 581 K

R = 8.314 JK - 1 mol - 1

Now, the fraction of molecules of reactants having energy equal to or greater than activation energy is given as