Chemistry, asked by mahalakshmi07, 8 months ago

The activation energy of a reaction is 94.14 kJ mor' and the value of rate constant at 313 K
is 1.8 x 10s Calculate the frequency factor, A.​

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Answered by Anonymous
0

Answer:

The activation energy of a reaction is 94.14 kJ mor' and the value of rate constant at 313 K

is 1.8 x 10sThe activation energy of a reaction is 94.14 kJ mor' and the value of rate constant at 313 K

is 1.8 x 10sThe activation energy of a reaction is 94.14 kJ mor' and the value of rate constant at 313 K

is 1.8 x 10s.

Answered by Prakshi1415
1

Answer:

</strong><strong>A</strong><strong> = 9.194 \times  {10}^{10} collisons

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