Question

The active ingredient in aspirin is
acetyl salicylic acid (molecular
formula C,H,04) with
K = 4.0x10-9
. The pH of the
solution obtained by dissolving
two aspirin tablets (containing
0.36 g of acetyl salicylic acid in
each tablet) in 250 ml of water is
(log 2 = 0.3)​

Answer 1

Answer:

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