Question

The Active Mass Of 5.6 Litres Of At Stp Is_____.

Answer 1

★ QuestioN :

Active mass of 5.6 litre N2 at STP is

$\rule{200}{2}$

★ AnSwEr :

We know that, at STP 22.4 L of volume is occupied by 1 mole of a gas.

So,

→ 5.6 L of volume of nitrogen gas occupied = $\sf{\frac{5.6}{22.4}}$

→ 5.6 L of volume of nitrogen gas occupied = 0.25 mole

$\rule{150}{2}$

→ Molar mass of N2 = 2 * 14

We know that,

$\Large{\implies{\boxed{\boxed{\sf{No. \: of \: moles = \dfrac{Given \: Mass}{Molar \: mass}}}}}}$

★ Putting Values ★

$\sf{\dashrightarrow 0.25 = \dfrac{Given \: Mass}{28}} \\ \\ \sf{\dashrightarrow Given \: Mass = 0.25 \times 28} \\ \\ \sf{\dashrightarrow Given \: Mass = 7 } \\ \\ \Large{\implies{\boxed{\boxed{\sf{Given \: Mass = 7 \: g}}}}}$