The active mass of 64 gm of HI in a 2-L flask would be:
(a) 2
(b) 1
(c) 5
(d) 0.25
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Molecular mass of HI = 128g/mol
Given mass of HI = 64g
Volume = 2L
Active mass is equal to the concentration of the solution.
Active mass of HI = Given Mass/Molecular mass×Volume = 64128×2 = 0.25
Correct option is (d) 0.25
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if not then comment me
Given mass of HI = 64g
Volume = 2L
Active mass is equal to the concentration of the solution.
Active mass of HI = Given Mass/Molecular mass×Volume = 64128×2 = 0.25
Correct option is (d) 0.25
I hope this will help you
if not then comment me
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