Chemistry, asked by sanketmule9823, 6 months ago


The actual mass of a 37ci atom is 36.966 amu. Calculate the mass defect (amu/atom) for a 37ci
atom.
0.623 amu
0 0.388 amu
0.263 amu
O 0.341 amu

Answers

Answered by chandanakavididevi85
2

Answer:

Well, you take the theoretical mass of combining all the particles, and subtract from it the actual isotopic mass. That mass accounts ... = 14.11626936 amu/atom−14.003241989 amu/ato

Answered by dindu890612
1

he actual mass of a 37ci atom is 36.966 amu. Calculate the mass defect (amu/atom) for a 37ci atom is 0.341 amu

Explanation:,

The actual mass of ₃₇Cl¹⁷ = 36.966amu

no. of proton in ₃₇Cl¹⁷ = 17

no. of the neutron in ₃₇Cl¹⁷ = 20

mass of the proton = 1.00728

mass of neutron = 1.00867

We know that,

Defect mass = {(no. of proton × mass of proton) + (no. of neutrons × mass of neutron)} - actual mass

Δm = {(17 × 1.00728) + ( 20 × 1.00867)} - 36.966

Δm = (17.123760 + 20.173400) - 36.966

Δm = 37.297160 - 36.966

Δm = 0.341amu

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