The actual mass of a 37ci atom is 36.966 amu. Calculate the mass defect (amu/atom) for a 37ci
atom.
0.623 amu
0 0.388 amu
0.263 amu
O 0.341 amu
Answers
Answered by
2
Answer:
Well, you take the theoretical mass of combining all the particles, and subtract from it the actual isotopic mass. That mass accounts ... = 14.11626936 amu/atom−14.003241989 amu/ato
Answered by
1
he actual mass of a 37ci atom is 36.966 amu. Calculate the mass defect (amu/atom) for a 37ci atom is 0.341 amu
Explanation:,
The actual mass of ₃₇Cl¹⁷ = 36.966amu
no. of proton in ₃₇Cl¹⁷ = 17
no. of the neutron in ₃₇Cl¹⁷ = 20
mass of the proton = 1.00728
mass of neutron = 1.00867
We know that,
Defect mass = {(no. of proton × mass of proton) + (no. of neutrons × mass of neutron)} - actual mass
Δm = {(17 × 1.00728) + ( 20 × 1.00867)} - 36.966
Δm = (17.123760 + 20.173400) - 36.966
Δm = 37.297160 - 36.966
Δm = 0.341amu
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