The actual mass of a 37Cl atom is 36.966 amu. Calculate the mass defect (amu/atom) for a 37Cl atom
Answers
The sum of the masses of components of atom (Neutron+Proton+Electron) and measured atomic mass is considered as Mass
The actual mass of a 37 Cl atom is 36.966 amu, Calculate the mass defect for a 37 ci atom in amu. You may use information about particle masses provided below. Masses Deuterium: 2.014102 amu Tritium: 3.016049 amu Helium:4.002603 amu mneutron: 1.008665 amu mproton = 1.007276 amu melectron = 0.000549 amu
Answer:
Mass defect for 37CL atom is 0.331 amu
Explanation:
Nuclear binding energy:
We have visible that the nucleus is made from neutrons and protons. Therefore it can be predicted that the mass of the nucleus is the same as the entire mass of its individual protons and neutrons. However, the nuclear mass M is discovered to be usually much less than the entire mass of its individual protons and neutrons.
The difference in the mass of a nucleus and its elements is referred to as the mass illness, and is given as,
⇒ ΔM = [Zm + (A-Z)m ] - M
Where ΔM = mass defect, Z = atomic quantity, A = mass quantity, m = mass of the proton, m = mass of the neutron, and M = actual mass of a nucleus
- If a positive quantity of neutrons and protons are brought together to form a nucleus of a positive rate and mass, the energy E may be launched withinside the process. The energy E is referred to as the binding energy of the nucleus.
- If we separate a nucleus into its nucleons, we'd supply total energy same to E, to the particles of the one particle.
- The ratio of the binding energy E of a nucleus to the number of nucleons A is referred to as the binding energy in keeping with nucleon E.
Given, M = 36.966 amu, Z = 17, A = 37, m = 1.00727 amu, and m = 1.00866 amu
We realize that the theoretical mass of the is given as,
⇒ Mth = [Zm + (A - Z)m ]
⇒ Mth = [17 × 1.00727 + (37 - 17) × 1.00866] amu
⇒ Mth = 37.297 amu
The mass defect of is given as,
⇒ ΔM = Mth - M
⇒ ΔM = (37.297 - 36.966) amu
⇒ ΔM = 0.331 amu
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