The acute angle at which the circles (x – 1)2 + (y – 4)2 = 1 and x2 + (y – 2)2 = 5 intersect is k° then k is divisible by
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Given : (x – 1)² + (y – 4)² = 1 and x² + (y – 2)² = 5
To Find : acute angle at which circle intersects
Solution:
(x – 1)² + (y – 4)² = 1
center = ( 1 , 4)
radius = 1
x² + (y – 2)² = 5
center = ( 0 , 2)
radius = √5
Distance between centers
( 1 , 4) and ( 0 , 2)
= √(1 - 0)² + (4 - 2)²
= √5
AB² = AC² + BC² - 2AC.BC.Cosα
=> 5 = 1 + 5 - 2(1)√5Cosα
=> Cosα = 1/2√5
=> α = 77.08°
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