Question

The acute angle between the planes 2x-y+z-6=0 and x+y2z=0 is​

Answer 1

Answer:

3π

Explanation:

Plane 1: 2x−y+z=6

normal vector is n1ˉ=2i^−j^+k^

Plane 2: x+y+2z=7

normal vector is n2ˉ=i^+j^+2k^

Angle between planes is same as the angle between their normal.

⇒cosθ=∣n1ˉ∣∣n2ˉ∣n1ˉ⋅n2ˉ

=(4+1+1)1+1+4(2i^−j^+k^)⋅(i^+j^+2k^)

=