The acute angles of a right angled triangle are in the ratio of 2:3.Find the angles of the triangle
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Answered by
30
let the angle =x
2x+3x+9 0 degrees =180 degrees
5x=180-90 degrees
5x =90
x=90/5=18 degrees
1st angle =2*18=36 degrees
2nd angle=3*18=54 degrees
2x+3x+9 0 degrees =180 degrees
5x=180-90 degrees
5x =90
x=90/5=18 degrees
1st angle =2*18=36 degrees
2nd angle=3*18=54 degrees
Answered by
10
Since it's a right angled triangle then one of the angles must be 90° (ninety degrees). The sum of the angles in a triangle is 180° (one hundred and eighty degrees) and the sum of the remaining (acute) angles in this triangle is 180° - 90° = 90°.
Let the first one be equal to 2x and the second one be 3x. The sum of 2x and 3x is 90°.
2x + 3x = 90°
(2 + 3)x = 90°
5x = 90°
x = 90°/5
x = 18°
The first angle is 90°.
The second one is 2x or 2 x 18° ==> 36°.
The third one is 3x or 3 x 18° ==> 54°.
Let the first one be equal to 2x and the second one be 3x. The sum of 2x and 3x is 90°.
2x + 3x = 90°
(2 + 3)x = 90°
5x = 90°
x = 90°/5
x = 18°
The first angle is 90°.
The second one is 2x or 2 x 18° ==> 36°.
The third one is 3x or 3 x 18° ==> 54°.
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