the acute angles of a right angled triangle are in the ratio of 3:7 . find the angles
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22
The angles are in the ratio 3:7.
In a right angled triangle the sum of acute angles is 90.
3x+7x=90
x=9.
Therefore the angles are
3*9=27
7*9=63.
Obviously the other angle is 90.
In a right angled triangle the sum of acute angles is 90.
3x+7x=90
x=9.
Therefore the angles are
3*9=27
7*9=63.
Obviously the other angle is 90.
Answered by
16
By the Angle sum property, Sum of angles in a triangle equals 180°
In right triangle, One angle = 90
so Angle A + B +90=180
Now A+B =90.
Given that acute angles are in the ratio 3:7
let them be 3x , 7x
So, 3x + 7x =90
10 x =90
Therefore, The acute angles are 27°,63°
In right triangle, One angle = 90
so Angle A + B +90=180
Now A+B =90.
Given that acute angles are in the ratio 3:7
let them be 3x , 7x
So, 3x + 7x =90
10 x =90
Therefore, The acute angles are 27°,63°
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